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Twelve balls are distribute among three boxes. The probability that the first box contains three balls is `(110)/9(2/3)^(10)` b. `(110)/9(2/3)^(10)` c. `(^(12)C_3)/(12^3)xx2^9` d. `(^(12)C_3)/(3^(12))`

A

`110/9(2/3)^(10)`

B

`110/9(3/2)^(10)`

C

`(.^(12)C_(3))/(3^(12))`

D

`(.^(12)C_(3))/(12^(3))`

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