A die is thrown, find the probability of following events: (i) A prime number will appear, (ii) A number greater than or equal to 3 will appear, (iii) A number less than or equal to one will appear, (iv) A number more than 6 will appear, (v

Answer

N/a

Explanation

In a throw of a die
Samle space `S={1,2,3,4,5,6}`
`impliesn(S)=6`
(i) Let `A=` event of getting a prime number
`={2,3,5}`
`impliesn(A)=3`
`:.` Probability of event A is `P(A)=(n(A))/(n(S))=3/6=1/2`
(ii) Let `B=` event of getting a number 3 or greater
`={3,4,5,6}`
`impliesn(B)=4`
`:.` Probability of event B is `P(B)=(n(B))/(n(S))=4/6=2/3`
(iii) Let `C=` event of getting a number 1 or smaller
`={1}`
`impliesn(C)=1`
`:.` Probability of event C is `P(C)=(n(C))/(n(S))=1/6`
(iv) Let `D=` event of getting a number greater than 6
`={}`
`impliesn(D)=0`
`:.` Probability of event D is `P(D)=(n(D))/(n(S))=0/6=0`
(v) Let `E=` event of getting number smaller than 6
`={1,2,3,4,5}`
`implies n(E)=5`
`:.` Probability of event E is `P(E)=(n(E))/(n(S))=5/6`