A fair coin with 1 marked on one face and 6 on the other and a fair die are both tossed, find the probability that the sum of numbers that turn up is (i) 3 (ii) 12

Answer

N/a

Explanation

Fair coin is marked 1 on one face and 6 on other face.
When this coin and a die is thrown together. Sample space `S={(1,1,)(1,2),(1,3),(1,4),(1,5),`
`(1,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}`
`implies n(S)=12`
(i) Event of getting the sum of numbers 3
`A={(1,2)}`
`impliesn(A)=1`
`:.` Probability of this event `P(A)=(n(A))/(n(S))=1/12`
(ii) Event of getting the sum of numbers 12
`B={(6,6)}`
`implies n(B)=1`
`:.` Probability of this event `P(B)=(n(B))/(n(S))=1/12`