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A and B are events such that P(A) = 0. 4...

A and B are events such that `P(A) = 0. 42`, `P(B) = 0. 48`and `P(A a n d B) = 0. 16`. Determine (i) P(not A), (ii) P(not B) and (iii) P(A or B)

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The correct Answer is:
N/a

Here `P(A)=0.42, P(B)=0.48`,
`P(AnnB)=0.16`
(i) `P` (A-not)`=P(A')`
`=1-P(A)`
`=1-0.42=0.58`
(ii)`P` (B-not) `=P(B')`
`=1-P(B)`
`=1-0.48=0.52`
(iii) `P` (A or B)`=P(AuuB)`
`=P(A)+P(B)-P(AnnB)`
`=0.42+0.48-0.16`
`=0.74`
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