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In the given figure, prove that AC = BD....

In the given figure, prove that `AC = BD`.

Text Solution

Verified by Experts

In `DeltaAPC` and `DeltaBPD`,
`:' {(AP,=,BP,"(given)"),(angleAPC,=,angleBPD,"(vertically opposite angle)"),(CP,=,DP,"(given)"):}`
`:. DeltaAP cong DeltaBPD` (SAS)
Hence, `AC = BD` (c.p.c.t)
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