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In the given figure, PS=PR, angleTPS=ang...

In the given figure, `PS=PR, angleTPS=angleQPR`. Prove that `PT=PQ`.

Text Solution

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Since `PS=PR` (given)
`:. angle4=angle3` (angle opposite to equal sides are equal)
`implies" "180-angle6=180-angle5` (L.P.A.)
`implies" "angle6=angle5`
Now, in `DeltaPST` and `DeltaPRQ`,
`:' {(angle5=angle6,"(just proved)"),(PS=PR,"(given)"),(angle1=angle2,"(given)"):}`
`:. DeltaPST cong DeltaPRQ` (ASA)
`:. PT = PQ` (c.p.c.t) Hence Proved.
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