Home
Class 9
MATHS
In the following figure, OA = OC and AB ...

In the following figure, OA = OC and AB = BC. Prove that :
(i) `angle AOB = 90^(@)`
(ii) `Delta AOD ~= Delta COD`
(iii) AD = CD

Promotional Banner

Topper's Solved these Questions

  • TRIANGLES

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 7b|17 Videos
  • TRIANGLES

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise (very Short Answer Questions)|10 Videos
  • TRIANGLES

    NAGEEN PRAKASHAN ENGLISH|Exercise Problems From NCERT/exemplar|5 Videos
  • SURFACE AREA AND VOLUME

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise (long Answer Questions)|10 Videos

Similar Questions

Explore conceptually related problems

In the following figure, OA=OC and AB=BC . Prove that : AD=CD

In the following figure, OA=OC and AB=BC . Prove that : angleAOB=90^(@)

In the following figure, OA=OC and AB=BC . Prove that : DeltaAOD~=DeltaCOD

In the following figure, angle A = angle C and AB = BC. Prove that : Delta ABD ~= Delta CBE

In the following figure, AB = EF, BC = DE and angle B = angle E = 90^(@) . Pove that AD = FC.

In the given figure, AB||CD and AB=CD , prove that: triangle AOB is congruent to triangle DOC.

In the following figure ABC is a right angled triangle with angleBAC=90^(@),andADbotBC . (i) Prove DeltaADB~DeltaCDA .

In the given figure, AD = DB = DE angle EAC = angle FAC and angle F = 90 ^(@) Prove that (i) angle AEB = 90 ^(@) (ii) Delta CEG is isosceles. (iii) angle CEG = angle EAF

In the given figure , BC = CE and angle 1 = angle 2. Prove that : Delta GCB = Delta DCB .

The following figure shows a triangle ABC in which AB = AC. M is a point on AB and N is a point on AC such that BM = CN. Prove that : (i) AM = AN (ii) Delta AMC ~= Delta ANB (iii) BN = CM (iv) Delta BMC ~= Delta CNB

NAGEEN PRAKASHAN ENGLISH-TRIANGLES-Exercise 7a
  1. The following figure shows a square ABCD and an equilateral triangle D...

    Text Solution

    |

  2. The given figure shows a parallelogram ABCD. Squares ABPQ and ADRS are...

    Text Solution

    |

  3. In a Delta ABC, BD is the median to the side AC, BD is produced to E s...

    Text Solution

    |

  4. In the given figure, angleBDC=angleBEA and AB = BC. Show that AE=CD.

    Text Solution

    |

  5. If the diagonals of a quadrilateral bisect each other at right angle, ...

    Text Solution

    |

  6. In the adjoining figure, BM and DN are the perpendiculars from B and D...

    Text Solution

    |

  7. In the adjoining figure, AB=EF, BC=DE, angleABC=angleFED=90^(@), prove...

    Text Solution

    |

  8. In the adjoining figure, ABCD is a parallelogram. If angleMBC = angleN...

    Text Solution

    |

  9. In the adjoining figure, QX and RX are the bisectors of the angles Q a...

    Text Solution

    |

  10. In the following figure, OA = OC and AB = BC. Prove that : (i) angle...

    Text Solution

    |

  11. In the adjoining figure, ABCD is a paralogram. The side AB is produced...

    Text Solution

    |

  12. In the following figures, AB=PQ, AC=PR and AM=PN. Prove that DeltaABC ...

    Text Solution

    |

  13. Prove that the medians of an equilateral triangle are equal.

    Text Solution

    |

  14. ABCD is a square EF is parallel to BD. R is the mid-point of EF. Prove...

    Text Solution

    |

  15. The following figure shows a triangle ABC in which AB = AC. M is a poi...

    Text Solution

    |

  16. In the given figure, AB"||"DC and angleD=angleC. Prove that : (i) AD...

    Text Solution

    |

  17. In the given figure : AB//FD, AC//GE and BD = CE, prove that : (i) B...

    Text Solution

    |

  18. In the adjoining figure, angleAYZ=angleBYX=90^(@), AY = YZ and XY = BY...

    Text Solution

    |

  19. In the adjoining figure, ABCD is a square and PAB is an equilateral tr...

    Text Solution

    |

  20. In the adjoining figure, DeltaABC is right angled at C and M is the mi...

    Text Solution

    |