Home
Class 9
MATHS
ABCD is a square EF is parallel to BD. R...

ABCD is a square EF is parallel to BD. R is the mid-point of EF. Prove that :
(i) `BE = DF`
(ii) AR bisects angle BAD
(iii) If AR produced it will pass through C.

Promotional Banner

Topper's Solved these Questions

  • TRIANGLES

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 7b|17 Videos

  • TRIANGLES

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise (very Short Answer Questions)|10 Videos

  • TRIANGLES

    NAGEEN PRAKASHAN ENGLISH|Exercise Problems From NCERT/exemplar|5 Videos

  • SURFACE AREA AND VOLUME

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise (long Answer Questions)|10 Videos

Similar Questions

Explore conceptually related problems

In parallelogram ABCD, E is the mid-point of side AB and CE bisect angle BCD. Prove that : (i) AE=AD (ii) DE bisect angleADC and (iii) Angle DEC is a right angle.

ABCD is a square, X is the mid-point of AB and Y the mid-point of BC. Prove that angle DXA = angle AYB

ABCD is a parallelogram E is mid-point of AB and DE bisects angle D. Prove that BC= BE

In Figure, O is the mid point of A B and C D . Prove that (i) A O C~= B O D (ii) AC=BD

ABCD is a parallelogram E is mid-point of AB and DE bisects angle D. Prove that CE bisects angle C

In Delta ABC , AB = AC and the bisectors of angles B and C intersect at point O. Prove that : (i) BO = CO (ii) AO bisects angle BAC.

ABCD is a square. E and F are respectively the mid-points of BC and CD. If R is the mid-point of EF, prove that ar (DeltaAER) = ar (DeltaAFR) .

ABCD is a parallelogram E is mid-point of AB and DE bisects angle D. Prove that angleDEC= 90^(@)

In a quadrilateral ABCD, AB = AD and CB = CD. Prove that : (i) AC bisects angle BAD (ii) AC is perpendicular bisector of BD.

From the given diagram, in which ABCD is a parallelgram, ABL is a line segment and E is mid point of BC. Prove that : (i) Delta DCE ~= Delta LBE (ii) AB = BL (iii) AL = 2DC

NAGEEN PRAKASHAN ENGLISH-TRIANGLES-Exercise 7a
  1. The following figure shows a square ABCD and an equilateral triangle D...

    Text Solution

    |

  2. The given figure shows a parallelogram ABCD. Squares ABPQ and ADRS are...

    Text Solution

    |

  3. In a Delta ABC, BD is the median to the side AC, BD is produced to E s...

    Text Solution

    |

  4. In the given figure, angleBDC=angleBEA and AB = BC. Show that AE=CD.

    Text Solution

    |

  5. If the diagonals of a quadrilateral bisect each other at right angle, ...

    Text Solution

    |

  6. In the adjoining figure, BM and DN are the perpendiculars from B and D...

    Text Solution

    |

  7. In the adjoining figure, AB=EF, BC=DE, angleABC=angleFED=90^(@), prove...

    Text Solution

    |

  8. In the adjoining figure, ABCD is a parallelogram. If angleMBC = angleN...

    Text Solution

    |

  9. In the adjoining figure, QX and RX are the bisectors of the angles Q a...

    Text Solution

    |

  10. In the following figure, OA = OC and AB = BC. Prove that : (i) angle...

    Text Solution

    |

  11. In the adjoining figure, ABCD is a paralogram. The side AB is produced...

    Text Solution

    |

  12. In the following figures, AB=PQ, AC=PR and AM=PN. Prove that DeltaABC ...

    Text Solution

    |

  13. Prove that the medians of an equilateral triangle are equal.

    Text Solution

    |

  14. ABCD is a square EF is parallel to BD. R is the mid-point of EF. Prove...

    Text Solution

    |

  15. The following figure shows a triangle ABC in which AB = AC. M is a poi...

    Text Solution

    |

  16. In the given figure, AB"||"DC and angleD=angleC. Prove that : (i) AD...

    Text Solution

    |

  17. In the given figure : AB//FD, AC//GE and BD = CE, prove that : (i) B...

    Text Solution

    |

  18. In the adjoining figure, angleAYZ=angleBYX=90^(@), AY = YZ and XY = BY...

    Text Solution

    |

  19. In the adjoining figure, ABCD is a square and PAB is an equilateral tr...

    Text Solution

    |

  20. In the adjoining figure, DeltaABC is right angled at C and M is the mi...

    Text Solution

    |