The given figure shows a quadrilateral ABCD. Prove that :
`AB+BC+CD+DA gt AC+BD`

Show that in a quadrilateral ABCD AB+BC+CD+DA gt AC + BD

In the adjoining figure, the diagonals AC and BD of a quadrilateral ABCD intersect point O. Prove that : AB+BC+CD+DA lt 2(AC+BD)

A quadrilateral ABCD is drawn to circumscribe a circle. Prove that AB+CD=AD+BC. or A circle touches all the four sides of a quadrilateral ABCD. Prove that AB+CD=BC+DA.

In the given figure ABCD is a parallelogram. Prove that AB = 2BC.

In a quadrilateral ABCD, prove that : (i) AB+BC+CD gt DA (ii) AB+BC+CD+DA gt 2AC (iii) AB+BC+CD+DA gt 2BD

Show that in a quadrilateral ABCD AB+BC+CD+DA lt 2 (BD + AC)

ABCD is a quadrilateral. Is AB+BC+CD+DA > AC+BD ?

If the sides of a quadrilateral ABCD touch a circle prove that AB+CD=BC+AD.

The given figure shows an equilateral triangles ABC and D is point in AC. Prove that : (i) AD lt BD (ii) BC gt BD

ABCD is quadrilateral. Is AB+BC+CD+DA < 2(AC+BD) ?