Construct a right triangle whose base is `12 c m\ ` and sum of its hypotenuse and other side is `18 c m`

Explanation

Given that, in `DeltaABC`, base BC = 12 cm, `angleB = 90^(@)` and AB + BC = 18 cm.
1. Draw the base BC = 12 cm.
2. At the point B, make an `angleXBC = 90^(@)`.
3. Cut a line segment BD = AB + AC 18 cm from the ray BX.
4. Join DC.
Draw the perpendicular bisector PQ of CD to intersect BD at a point A.
6. Join AC.
Then, ABC is the required right angled triangle.