If origin is shifted to the point `(-1,2)` then what will be the transformed equation of the curve `2x^(2)+y^(2)-3x+4y-1=0` in the new axes ?

Explanation

To find the transformed equation of the curve \(2x^2 + y^2 - 3x + 4y - 1 = 0\) after shifting the origin to the point \((-1, 2)\), we can follow these steps:

### Step 1: Identify the new coordinates
When the origin is shifted to a new point \((h, k)\), the relationship between the old coordinates \((x, y)\) and the new coordinates \((X, Y)\) is given by:
\[ x = X + h \quad \text{and} \quad y = Y + k \]
In our case, \(h = -1\) and \(k = 2\). Therefore, we have:
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