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Find the equation of perpendicular bisector of line segment joining the points `(1,5)` and `(3,-1)`

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To find the equation of the perpendicular bisector of the line segment joining the points \( A(1, 5) \) and \( B(3, -1) \), we will follow these steps: ### Step 1: Find the Midpoint of the Line Segment The midpoint \( M \) of the line segment joining two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is given by the formula: \[ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \] For points \( A(1, 5) \) and \( B(3, -1) \): - \( x_1 = 1, y_1 = 5 \) - \( x_2 = 3, y_2 = -1 \) Calculating the midpoint: \[ M = \left( \frac{1 + 3}{2}, \frac{5 + (-1)}{2} \right) = \left( \frac{4}{2}, \frac{4}{2} \right) = (2, 2) \] ### Step 2: Find the Slope of Line Segment AB The slope \( m \) of the line segment joining two points is given by: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] Calculating the slope for points \( A(1, 5) \) and \( B(3, -1) \): \[ m_{AB} = \frac{-1 - 5}{3 - 1} = \frac{-6}{2} = -3 \] ### Step 3: Find the Slope of the Perpendicular Bisector The slope of the perpendicular bisector \( m_{PB} \) is the negative reciprocal of the slope of line segment \( AB \): \[ m_{PB} = -\frac{1}{m_{AB}} = -\frac{1}{-3} = \frac{1}{3} \] ### Step 4: Use the Point-Slope Form to Find the Equation The equation of a line in point-slope form is given by: \[ y - y_1 = m(x - x_1) \] Using the midpoint \( M(2, 2) \) and the slope \( m_{PB} = \frac{1}{3} \): \[ y - 2 = \frac{1}{3}(x - 2) \] ### Step 5: Simplify the Equation Expanding the equation: \[ y - 2 = \frac{1}{3}x - \frac{2}{3} \] Adding \( 2 \) to both sides: \[ y = \frac{1}{3}x - \frac{2}{3} + 2 \] Converting \( 2 \) to a fraction with a denominator of 3: \[ y = \frac{1}{3}x - \frac{2}{3} + \frac{6}{3} = \frac{1}{3}x + \frac{4}{3} \] ### Step 6: Convert to Standard Form To convert to standard form \( Ax + By + C = 0 \): \[ 3y = x + 4 \quad \Rightarrow \quad x - 3y + 4 = 0 \] ### Final Answer The equation of the perpendicular bisector is: \[ \boxed{x - 3y + 4 = 0} \]
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