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Find the length of perpendicular from or...

Find the length of perpendicular from origin to the line `x+7y+4sqrt(2)=0`.

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To find the length of the perpendicular from the origin to the line given by the equation \( x + 7y + 4\sqrt{2} = 0 \), we will use the formula for the distance \( d \) from a point \( (x_1, y_1) \) to a line given by the equation \( Ax + By + C = 0 \): \[ d = \frac{|Ax_1 + By_1 + C|}{\sqrt{A^2 + B^2}} \] ### Step-by-Step Solution: 1. **Identify the coefficients**: From the line equation \( x + 7y + 4\sqrt{2} = 0 \), we can identify: - \( A = 1 \) - \( B = 7 \) - \( C = 4\sqrt{2} \) 2. **Identify the point**: We need to find the distance from the origin, which has coordinates \( (x_1, y_1) = (0, 0) \). 3. **Substitute into the distance formula**: Substitute \( A \), \( B \), \( C \), \( x_1 \), and \( y_1 \) into the distance formula: \[ d = \frac{|1 \cdot 0 + 7 \cdot 0 + 4\sqrt{2}|}{\sqrt{1^2 + 7^2}} \] 4. **Calculate the numerator**: The numerator simplifies to: \[ |0 + 0 + 4\sqrt{2}| = |4\sqrt{2}| = 4\sqrt{2} \] 5. **Calculate the denominator**: The denominator simplifies to: \[ \sqrt{1^2 + 7^2} = \sqrt{1 + 49} = \sqrt{50} = 5\sqrt{2} \] 6. **Combine the results**: Now, substitute the values back into the formula: \[ d = \frac{4\sqrt{2}}{5\sqrt{2}} \] 7. **Simplify**: The \( \sqrt{2} \) in the numerator and denominator cancels out: \[ d = \frac{4}{5} \] ### Final Answer: The length of the perpendicular from the origin to the line \( x + 7y + 4\sqrt{2} = 0 \) is \( \frac{4}{5} \).
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