Home
Class 11
MATHS
The co-ordinates of the foot of perpendi...

The co-ordinates of the foot of perpendicular drawn from origin to a line are `(2,3)`. Find the equation of the line.

Text Solution

AI Generated Solution

The correct Answer is:
To find the equation of the line given the coordinates of the foot of the perpendicular from the origin to the line, we can follow these steps: ### Step 1: Identify the coordinates of the foot of the perpendicular The coordinates of the foot of the perpendicular from the origin (0, 0) to the line are given as (2, 3). ### Step 2: Determine the slope of the line from the origin to the foot of the perpendicular The slope (m) of the line segment from the origin (0, 0) to the point (2, 3) can be calculated using the formula: \[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{3 - 0}{2 - 0} = \frac{3}{2} \] ### Step 3: Write the equation of the line from the origin to the foot of the perpendicular Using the point-slope form of the equation of a line, which is given by: \[ y - y_1 = m(x - x_1) \] we can substitute \(m = \frac{3}{2}\), \(x_1 = 0\), and \(y_1 = 0\): \[ y - 0 = \frac{3}{2}(x - 0) \implies y = \frac{3}{2}x \] ### Step 4: Convert the equation to standard form To convert \(y = \frac{3}{2}x\) to standard form \(Ax + By + C = 0\), we can rearrange it: \[ -\frac{3}{2}x + y = 0 \implies 3x - 2y = 0 \] ### Step 5: Find the equation of the line perpendicular to this line For a line perpendicular to another line, the slopes are negative reciprocals. The slope of the line we found is \(\frac{3}{2}\), so the slope of the perpendicular line will be: \[ -\frac{1}{\frac{3}{2}} = -\frac{2}{3} \] ### Step 6: Use the foot of the perpendicular to write the equation of the perpendicular line Using the point-slope form again for the line with slope \(-\frac{2}{3}\) passing through the point (2, 3): \[ y - 3 = -\frac{2}{3}(x - 2) \] ### Step 7: Simplify the equation Distributing the slope: \[ y - 3 = -\frac{2}{3}x + \frac{4}{3} \] Adding 3 to both sides: \[ y = -\frac{2}{3}x + \frac{4}{3} + 3 \] Converting 3 to a fraction: \[ y = -\frac{2}{3}x + \frac{4}{3} + \frac{9}{3} = -\frac{2}{3}x + \frac{13}{3} \] ### Step 8: Convert to standard form Multiplying through by 3 to eliminate the fraction: \[ 3y = -2x + 13 \implies 2x + 3y - 13 = 0 \] ### Final Answer The equation of the line is: \[ 2x + 3y - 13 = 0 \] ---
Promotional Banner

Topper's Solved these Questions

  • STRAIGHT LINES

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise|207 Videos
  • STATISTICS

    NAGEEN PRAKASHAN ENGLISH|Exercise MISCELLANEOUS EXERCISE|7 Videos
  • TRIGNOMETRIC FUNCTIONS

    NAGEEN PRAKASHAN ENGLISH|Exercise MISCELLANEOUS EXERCISE|10 Videos

Similar Questions

Explore conceptually related problems

The co-ordiantes of the foot of perpendicular from origin to a plane are (3,-2,1) . Find the equation of the plane.

The co-ordiantes of the foot of perpendicular from origin to a plane are (1,2,-3) . Find the eqution of the plane.

The coordinate of the foot of the perpendicular drawn from the origin to a plane are (12, -4, 3). Find the equation of the plane.

The foot of perpendicular drawn from the origin to the plane is (4,-2,-5)dot Find the equation of the plane.

Find the coordinates of the foot of perpendicular drawn from origin to the planes: 5y+8=0

Find the coordinates of the foot of perpendicular drawn from origin to the planes: x+y+z=1

Find the coordinates of the foot of perpendicular drawn from origin to the planes: 3y+4z-6=0

The foot of the perpendicular drawn from the origin to a plane is (1,2,-3)dot Find the equation of the plane. or If O is the origin and the coordinates of P is (1,2,-3), then find the equation of the plane passing through P and perpendicular to O Pdot

Find the coordinates of the foot of perpendicular drawn from origin to the planes: 2x-3y+4z-6=0

The perpendicular from the origin to a line meets it at the point (2,9) , find the equation of the line.

NAGEEN PRAKASHAN ENGLISH-STRAIGHT LINES-Exercise
  1. Find the length of perpendicular from origin to the line x+7y+4sqrt(2)...

    Text Solution

    |

  2. Find the distance between the parallel lines 5x+12y-20=0 and 5x+12y+6=...

    Text Solution

    |

  3. The co-ordinates of the foot of perpendicular drawn from origin to a l...

    Text Solution

    |

  4. Find the length of perpendicular from the point (a cos alpha, a sin al...

    Text Solution

    |

  5. Find the distance between the parallel lines x+4sqrt(3)y+10=0 and x+4s...

    Text Solution

    |

  6. Find the relation between a and b if the lines 3x-by+5=0 and ax+y=2 pa...

    Text Solution

    |

  7. If p and q are the lengths of perpendiculars from the origin to the l...

    Text Solution

    |

  8. Show that the distance between the parallel lines ax+by+c=0 and k(ax+b...

    Text Solution

    |

  9. If the length of perpendicular from origin to the line ax+by+a+b=0 is ...

    Text Solution

    |

  10. The equations of sides AB, BC and AC of DeltaABC are respectively y=x,...

    Text Solution

    |

  11. If p is the length of perpendicular from the origin to the line whose...

    Text Solution

    |

  12. Find the coordinates of the incentre and centroid of the triangle whos...

    Text Solution

    |

  13. Find the co-ordinates of the circumcentre of a triangle whose vertices...

    Text Solution

    |

  14. Find the co-ordinates of the orthocentre of a triangle whose vertices ...

    Text Solution

    |

  15. The equation of one diagonal of a square is 2x+y=6 and its one vertex ...

    Text Solution

    |

  16. The co-ordinates of the vertex of an equilateral triangle are (2,-1) a...

    Text Solution

    |

  17. A ray of light is rent along the line x-2y-3 = 0. Upon reaching the li...

    Text Solution

    |

  18. Find the equation of the straight line through the origin making angle...

    Text Solution

    |

  19. Show that the straight lines given by (2+k)x+(1+k)y=5+7k for different...

    Text Solution

    |

  20. Find the equation of a line passing through the point of intersection ...

    Text Solution

    |