Find the values of 6 and p, if the equation `xcostheta-ysintheta=p` is the normal form of the line `sqrt(3)x+y+2=0` .

Explanation

Given line, `sqrt(3)x+y+2=0`
`implies -sqrt(3)x-y=2`
Divide both sides by `sqrt((-sqrt(3))^(2)+(-1)^(2))=2`
`(-sqrt(3))/(2)*x+(-(1)/(2))y=1`
Comparing with `x cos theta +y sin theta =p`
`costheta=(-sqrt(3))/(2)`, `sintheta=-(1)/(2)`, `p=1`
`implies theta=210^(@)`, `p=1`