If three lines whose equations are `y=m_1x+c_1,y=m_2x+c_2`and `y=m_3x+c_3`are concurrent, then show that `m_1(c_2-c_3)+m_2(c_3-c_1)+m_3(c_1-c_2)=0`.

Explanation

To show that if three lines whose equations are \(y = m_1x + c_1\), \(y = m_2x + c_2\), and \(y = m_3x + c_3\) are concurrent, then the equation \(m_1(c_2 - c_3) + m_2(c_3 - c_1) + m_3(c_1 - c_2) = 0\) holds, we can follow these steps:

### Step 1: Rewrite the equations in standard form
The equations of the lines can be rewritten in the standard form \(Ax + By + C = 0\):
1. For the first line:
\[ m_1x - y + c_1 = 0 \]
...