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Find equation of the line which is eq...

Find equation of the line which is equidistant from parallel lines `9x" "+" "6y" "" "7" "=" "0` and `3x" "+" "2y" "+6" "=" "0` .

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To find the equation of the line that is equidistant from the two given parallel lines, we will follow these steps: ### Step 1: Write down the equations of the given lines. The two given lines are: 1. \( 9x + 6y - 7 = 0 \) 2. \( 3x + 2y + 6 = 0 \)
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NAGEEN PRAKASHAN ENGLISH-STRAIGHT LINES-Exercise
  1. Find perpendicular distance from the origin of the line joining the p...

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  2. Find the equation of the line parallel to y-axis and drawn through the...

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  3. Find the equation of a line drawn perpendicular to the line x/4+y/6 = ...

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  4. Find the area of the triangle formed by the lines y-x=0,x+y=0and x-k=0...

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  5. Find the value of p so that the three lines 3x + y - 2 = 0, p x + 2 y...

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  6. If three lines whose equations are y=m1x+c1,y=m2x+c2and y=m3x+c3are c...

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  7. Find the equation of the lines through the point (3, 2) which make an...

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  8. Find the equation of the line passing through the point of intersecti...

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  9. Show that the equation of the straight line through the origin angle v...

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  10. In what ratio, the line joining (1, 1)and (5, 7)is divided by the line...

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  11. Find the distance of the line 4x+7y+5=0 from the point (1,""""2) al...

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  12. Find the direction in which a straight line must be drawn through th...

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  13. The hypotenuse of a right angled triangle has its ends at the points...

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  14. Find the image of the point (3, 8)with respect to the line x + 3y = 7...

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  15. If the lines y" "=" "3x" "+" "1 and 2y" "=" "x" "+" "3 are equally ...

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  16. If sum of the perpendicular distances of a variable point P (x , y)fr...

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  17. Find equation of the line which is equidistant from parallel lines ...

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  18. A ray of light passing through the point (1, 2) reflects on the xax...

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  19. Prove that the product of the lengths of the perpendiculars drawn fro...

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  20. A person standing at the junction (crossing) of two straight paths rep...

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