Home
Class 11
MATHS
Find the number of terms in the G.P. 1, ...

Find the number of terms in the G.P. 1, 2, 4, 8, ... 4096.

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of terms in the geometric progression (G.P.) given by 1, 2, 4, 8, ..., 4096, we can follow these steps: ### Step 1: Identify the first term and common ratio The first term \( a \) of the G.P. is 1. The common ratio \( r \) can be calculated by dividing the second term by the first term: \[ r = \frac{2}{1} = 2 \] **Hint:** The first term is the initial value of the sequence, and the common ratio is found by dividing any term by its preceding term. ### Step 2: Write the formula for the nth term of a G.P. The formula for the nth term of a G.P. is given by: \[ a_n = a \cdot r^{n-1} \] where \( a_n \) is the nth term, \( a \) is the first term, \( r \) is the common ratio, and \( n \) is the number of terms. **Hint:** This formula helps us express any term in the sequence based on its position. ### Step 3: Set up the equation for the last term In this case, we know the last term \( a_n \) is 4096. Substituting the known values into the formula gives: \[ 4096 = 1 \cdot 2^{n-1} \] This simplifies to: \[ 4096 = 2^{n-1} \] **Hint:** Substitute the known last term into the nth term formula to find \( n \). ### Step 4: Express 4096 as a power of 2 We can express 4096 as a power of 2: \[ 4096 = 2^{12} \] **Hint:** Recognizing numbers as powers of their base can help simplify the equation. ### Step 5: Set the exponents equal to each other Since the bases are the same, we can set the exponents equal: \[ n - 1 = 12 \] **Hint:** When bases are the same, their exponents must also be equal. ### Step 6: Solve for \( n \) Now, solve for \( n \): \[ n = 12 + 1 = 13 \] **Hint:** Adding 1 accounts for the first term in the sequence. ### Conclusion The number of terms in the G.P. is 13. **Final Answer:** 13

To find the number of terms in the geometric progression (G.P.) given by 1, 2, 4, 8, ..., 4096, we can follow these steps: ### Step 1: Identify the first term and common ratio The first term \( a \) of the G.P. is 1. The common ratio \( r \) can be calculated by dividing the second term by the first term: \[ r = \frac{2}{1} = 2 \] ...
Promotional Banner

Topper's Solved these Questions

  • SEQUENCE AND SERIES

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 9G|17 Videos
  • SEQUENCE AND SERIES

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 9H|9 Videos
  • SEQUENCE AND SERIES

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 9E|15 Videos
  • RELATIONS AND FUNCTIONS

    NAGEEN PRAKASHAN ENGLISH|Exercise MISCELLANEOUS EXERCISE|12 Videos
  • SETS

    NAGEEN PRAKASHAN ENGLISH|Exercise MISC Exercise|16 Videos

Similar Questions

Explore conceptually related problems

Find the number of terms in the G.P. 1, - 3, 9, ... - 2187.

Find the sum of 8 terms of the G.P. : 3+6+12+24+ . . . . .. . . . . .

Find: the ninth term of the G.P. 1,4,16,64,………

Find the 7th term of the G.P. 4 ,-8 , 16, ... .

Find the 9th term of the G. P. 2, 1, (1)/(2) ,….

Find the 15th term of the G.P. 3/2,3/4,3/8,……

The fourth term of the G.P. 4, - 2 , 1 , … is

The first and last term of a geometrical Pregression (G.P.) are 3 and 96 respectively. If the common ratio is 2, find : (i) 'n' the number of terms of the G.P. (ii) Sum of the n terms.

Find the 10^(th) term of the G.P. : 12,4,1(1)/(3), . . . . . . . . . ..

Find: the 10th term of the G.P. -3/4,1/2,-1/3,2/9, ....

NAGEEN PRAKASHAN ENGLISH-SEQUENCE AND SERIES-Exercise 9F
  1. Find the 9th term of the G. P. 2, 1, (1)/(2),….

    Text Solution

    |

  2. Find the 8th term of the G.P. sqrt(3),(1)/(sqrt(3)),(1)/(3sqrt(3)),......

    Text Solution

    |

  3. Find the number of terms in the G.P. 1, 2, 4, 8, ... 4096.

    Text Solution

    |

  4. Find the number of terms in the G.P. 1, - 3, 9, ... - 2187.

    Text Solution

    |

  5. Find the 5th term from the end of the G .P. (1)/(512),(1)/(256),(1)/(1...

    Text Solution

    |

  6. Find the 4th term from the end of the G .P. (5)/(2),(15)/(8),(45)/(32)...

    Text Solution

    |

  7. Which term of the progression sqrt(3),3,3sqrt(3)... is 729 ?

    Text Solution

    |

  8. Which term of the G.P., 2, 8, 32, . . . up to n terms in 131072?

    Text Solution

    |

  9. If the nth terms of the progression 5, 10, 20, … and progression 1280,...

    Text Solution

    |

  10. The 3rd, 7th and 11th terms of a G.P. are x, y and z respectively, the...

    Text Solution

    |

  11. The 3rd and 6th terms of a G.P. are 40 and 320, then find the progress...

    Text Solution

    |

  12. Find the G.P. whose 2nd and 5th terms are -(3)/(2)" and "(81)/(16) r...

    Text Solution

    |

  13. in a G.P (p+q)th term = m and (p-q) th term = n , then find its p th t...

    Text Solution

    |

  14. Find the G.P. whose 2nd term is 12 and 6th term is 27 times the 3rd te...

    Text Solution

    |

  15. The first term of a G.P. is -3. If the 4th term of this G.P. is the sq...

    Text Solution

    |

  16. The 4th, 7th and last terms of a G.P. are 10,80 and 2560 respectively....

    Text Solution

    |

  17. Find the 4 terms in G .P. in which 3rd term is 9 more than the first t...

    Text Solution

    |

  18. A manufacturer reckons that the value of a machine, which costs him...

    Text Solution

    |

  19. In a G.P. it is given that T(p-1)+T(p+1)=3T(p). Prove that its common ...

    Text Solution

    |

  20. If k, k + 1 and k + 3 are in G.P. then find the value of k.

    Text Solution

    |