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If a, b, c are in GP, prove that a^ 2 ...

If a, b, c are in GP, prove that a^ 2 b^ 2 c ^ 2 ( 1/ a ^ 3 +1/ b ^ 3 ​ +1/ c ^ 3 ​ )=a ^ 3 +b^ 3 +c^ 3 .

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To prove that \( a^2 b^2 c^2 \left( \frac{1}{a^3} + \frac{1}{b^3} + \frac{1}{c^3} \right) = a^3 + b^3 + c^3 \) given that \( a, b, c \) are in geometric progression (GP), we can follow these steps: ### Step 1: Understand the relationship in GP Since \( a, b, c \) are in GP, we can express \( b \) in terms of \( a \) and \( c \): \[ b^2 = ac \] ...
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