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The sum of the squares of first 50 natur...

The sum of the squares of first 50 natural numbers is :

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To find the sum of the squares of the first 50 natural numbers, we can use the formula for the sum of squares of the first n natural numbers: \[ S_n = \frac{n(n + 1)(2n + 1)}{6} \] ### Step-by-step Solution: ...
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Statement - I : The variance of first n even natural numbers is (n^(2) - 1)/(4) Statement - II : The sum of first n natural numbers is (n(n+1))/(2) and the sum of the squares of first n natural numbers is (n(n+1)(2n+1))/(6)

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Knowledge Check

  • The sum of first 25 natural numbers is:

    A
    650
    B
    250
    C
    625
    D
    325
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