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The sum of n terms of an A.P. is (n^(2)+...

The sum of n terms of an A.P. is `(n^(2)+5n).` Its common difference is :

A

`1`

B

`4`

C

`2`

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the common difference of the arithmetic progression (A.P.) where the sum of the first n terms is given by \( S_n = n^2 + 5n \), we can follow these steps: ### Step 1: Find \( S_1 \) The first step is to calculate the sum of the first term \( S_1 \) by substituting \( n = 1 \) into the sum formula. \[ S_1 = 1^2 + 5 \cdot 1 = 1 + 5 = 6 \] This means that the first term \( a_1 \) of the A.P. is: \[ a_1 = S_1 = 6 \] ### Step 2: Find \( S_2 \) Next, we calculate the sum of the first two terms \( S_2 \) by substituting \( n = 2 \) into the sum formula. \[ S_2 = 2^2 + 5 \cdot 2 = 4 + 10 = 14 \] This means that the sum of the first two terms \( a_1 + a_2 \) is: \[ S_2 = a_1 + a_2 = 14 \] ### Step 3: Solve for \( a_2 \) Now we can substitute the value of \( a_1 \) into the equation for \( S_2 \): \[ 14 = 6 + a_2 \] To find \( a_2 \), we rearrange the equation: \[ a_2 = 14 - 6 = 8 \] ### Step 4: Find the common difference \( d \) The common difference \( d \) of the A.P. can be found using the formula: \[ d = a_2 - a_1 \] Substituting the values we found: \[ d = 8 - 6 = 2 \] ### Conclusion Thus, the common difference of the A.P. is: \[ \boxed{2} \] ---

To find the common difference of the arithmetic progression (A.P.) where the sum of the first n terms is given by \( S_n = n^2 + 5n \), we can follow these steps: ### Step 1: Find \( S_1 \) The first step is to calculate the sum of the first term \( S_1 \) by substituting \( n = 1 \) into the sum formula. \[ S_1 = 1^2 + 5 \cdot 1 = 1 + 5 = 6 \] ...
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