Write the first five terms of each of the sequences in Questions 1 to 6 whose nth terms are :
`a_(n)=(2n-3)/(6)`

Answer

N/a

Explanation

nth term of given sequence `a_(n)=(2n-3)/(6)`
`therefore" 1st term of given sequence "a_(1)=(2.1-3)/(6)=(2-3)/(6)=(-1)/(6),`
`therefore" 2nd term of given sequence "a_(2)=(2.2-3)/(6)=(4-3)/(6)=(1)/(6),`
`therefore" 3rd term of given sequence "a_(3)=(2.3-3)/(6)=(6-3)/(6)=(3)/(6)=(1)/(2),`
`therefore" 4th term of given sequence "a_(4)=(2.4-3)/(6)=(8-3)/(6)=(5)/(6),`
`therefore" 5th term of given sequence "a_(5)=(2.5-3)/(6)=(10-3)/(6)=(7)/(6),`
Therefore, first 5 terms of given sequence are
`a_(1)=(-1)/(6),a_(2)=(1)/(6),a_(3)=(1)/(2),a_(4)=(5)/(6),a_(5)=(7)/(6).`