Find four numbers forming a geometric progression in which the third term is greater than the first terms by 9, and second term is greater than the 4th by 18.

Answer

N/a

Explanation

Let first four terms of G.P are `a, ar, ar^(2),ar^(3)`
`ar^(2)-a=9 implies a(r^(2)-1)=9`…(1)
and `ar-ar^(3)=18 implies -ar(r^(2)-1)=18`
`implies -r*9=18 `[From equation (1)]
Put the value of r in equation
`a(4-1)=9implies a=3`
`:.` Four terms of the progression `=3,-6,12,-24`