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2x + y ge 6, 3x + 4y le 12...

`2x + y ge 6, 3x + 4y le 12`

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First inequation : `2x + y ge 6`
Corresponding equation : `2x + y = 6`
It cuts the X-axis at A(3, 0) and Y-axis at B (0, 6). Join AB. At point (0, 0), from the inequation, `0ge 6` (False)
`:.` Solution of this inequation is that region of XY-plane divided by line AB in which (0, 0) does not lie.
Second inequation : `3x + 4y le12`
Correstion equation : ` 3x + 4y = 12`
It cuts the X-axis at C(4, 0) and Y-axis at D (0, 3). Join CD.
At point (0, 0) , from the inequation, `0le 12`(True)
`:.` The solution of this inequation is that region of XY-plane divided by line CD in which (0, 0) lies.

The common solution of two inequation is shwon by the shaded part.
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