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If the coefficients of x^2a n d\ x^3 in ...

If the coefficients of `x^2a n d\ x^3` in the expansion o `(3+a x)^9` are the same, then the value of `a` is `-7/9` b. `-9/7` c. `7/9` d. `9/7`

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To solve the problem, we need to find the value of \( a \) such that the coefficients of \( x^2 \) and \( x^3 \) in the expansion of \( (3 + ax)^9 \) are equal. ### Step-by-Step Solution: 1. **Identify the General Term**: The general term in the binomial expansion of \( (3 + ax)^n \) is given by: \[ T_k = \binom{n}{k} (3)^{n-k} (ax)^k \] For our case, \( n = 9 \). 2. **Find the Coefficient of \( x^2 \)**: The coefficient of \( x^2 \) corresponds to \( k = 2 \): \[ T_2 = \binom{9}{2} (3)^{9-2} (ax)^2 = \binom{9}{2} (3)^7 a^2 \] The coefficient of \( x^2 \) is: \[ C_2 = \binom{9}{2} \cdot 3^7 \cdot a^2 \] 3. **Find the Coefficient of \( x^3 \)**: The coefficient of \( x^3 \) corresponds to \( k = 3 \): \[ T_3 = \binom{9}{3} (3)^{9-3} (ax)^3 = \binom{9}{3} (3)^6 (ax)^3 \] The coefficient of \( x^3 \) is: \[ C_3 = \binom{9}{3} \cdot 3^6 \cdot a^3 \] 4. **Set the Coefficients Equal**: Since the coefficients of \( x^2 \) and \( x^3 \) are the same, we have: \[ \binom{9}{2} \cdot 3^7 \cdot a^2 = \binom{9}{3} \cdot 3^6 \cdot a^3 \] 5. **Simplify the Equation**: We can simplify this equation: \[ \binom{9}{2} \cdot 3^7 \cdot a^2 = \binom{9}{3} \cdot 3^6 \cdot a^3 \] Dividing both sides by \( 3^6 \): \[ \binom{9}{2} \cdot 3 \cdot a^2 = \binom{9}{3} \cdot a^3 \] 6. **Calculate the Binomial Coefficients**: We know: \[ \binom{9}{2} = \frac{9 \times 8}{2 \times 1} = 36 \] \[ \binom{9}{3} = \frac{9 \times 8 \times 7}{3 \times 2 \times 1} = 84 \] Substituting these values into the equation gives: \[ 36 \cdot 3 \cdot a^2 = 84 \cdot a^3 \] Simplifying further: \[ 108 a^2 = 84 a^3 \] 7. **Rearranging the Equation**: Rearranging gives: \[ 84 a^3 - 108 a^2 = 0 \] Factoring out \( a^2 \): \[ a^2 (84 a - 108) = 0 \] 8. **Solving for \( a \)**: This gives us two solutions: \[ a^2 = 0 \quad \text{or} \quad 84 a - 108 = 0 \] The first gives \( a = 0 \) (not relevant here), and the second gives: \[ 84 a = 108 \implies a = \frac{108}{84} = \frac{9}{7} \] ### Final Answer: Thus, the value of \( a \) is \( \frac{9}{7} \).

To solve the problem, we need to find the value of \( a \) such that the coefficients of \( x^2 \) and \( x^3 \) in the expansion of \( (3 + ax)^9 \) are equal. ### Step-by-Step Solution: 1. **Identify the General Term**: The general term in the binomial expansion of \( (3 + ax)^n \) is given by: \[ T_k = \binom{n}{k} (3)^{n-k} (ax)^k ...
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NAGEEN PRAKASHAN ENGLISH-BINOMIAL THEOREM-Miscellaneous Exericse
  1. Find a, b and n in the expansion of (a+b)^nif the first three terms ...

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  2. If the coefficients of x^2a n d\ x^3 in the expansion o (3+a x)^9 are ...

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  3. Find the coefficient of a^4 in the product (1+a)^4(2-a)^5 using binomi...

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  4. If a and b are distinct integers, prove that a - b is a factor of a^n-...

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  5. Evaluate (sqrt(3)+sqrt(2))^6-(sqrt(3)-sqrt(2))^6dot

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  6. Find the value of (a^2+sqrt(a^2-1))^4+(a^2-sqrt(a^2-1))^4.

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  7. Find an approximation of (0. 99)^5 using the first three terms of its ...

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  8. Find n, if the ratio of the fifth term from the beginning to the fi...

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  9. Using binomial theorem expand (1+x/2-2/x)^4,\ x!=0.

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  10. Find the expansion of (3x^2-2a x+3a^2)^3 using binomial theorem.

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  11. Find a, b and n in the expansion of (a+b)^nif the first three terms ...

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  12. If the coefficients of x^2a n d\ x^3 in the expansion o (3+a x)^9 are ...

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  13. Find the coefficient of x^5 in the expansion of (1 + 2x)^6 (1-x)^7.

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  14. If a and b are distinct integers, prove that a - b is a factor of a^n-...

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  15. Evaluate (sqrt(3)+sqrt(2))^6-(sqrt(3)-sqrt(2))^6dot

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  16. Find the value of (a^2+sqrt(a^2-1))^4+(a^2-sqrt(a^2-1))^4.

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  17. Find an approximation of (0. 99)^5using the first three terms of its ...

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  18. Find n, if the ratio of the fifth term from the beginning to the fi...

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  19. Expand using Binomial Theorem (1+x/2-2/x)^4,x!=0.

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  20. Find the expansion of (3x^2-2a x+3a^2)^3 using binomial theorem.

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