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Find an approximation of (0. 99)^5using ...

Find an approximation of `(0. 99)^5`using the first three terms of its expansion.

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The correct Answer is:
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`(0.99)^(5)=(1-0.01)^(5)`
`=^(5)C_(0)-^(5)C_(1)(0.01)+^(5)C_(2)(0.01)^(2)-^(5)C_(3)(0.01)^(3)......`
`=1-5.(0.01)+10.(0.01)^(2)` (taking first three tems)
`=1-0.05+10xx0.0001`
`=0.95+0.0001 =0.9501`
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