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find inverse using elementary operations` [[6,-3],[-2,1]]`

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To find the inverse of the matrix \( A = \begin{pmatrix} 6 & -3 \\ -2 & 1 \end{pmatrix} \) using elementary operations, we will follow these steps: ### Step 1: Calculate the Determinant of Matrix A The determinant of a 2x2 matrix \( \begin{pmatrix} a & b \\ c & d \end{pmatrix} \) is calculated using the formula: \[ \text{det}(A) = ad - bc \] For our matrix \( A \): - \( a = 6 \) - \( b = -3 \) - \( c = -2 \) - \( d = 1 \) Calculating the determinant: \[ \text{det}(A) = (6)(1) - (-3)(-2) = 6 - 6 = 0 \] ### Step 2: Check the Determinant Since the determinant is \( 0 \), it indicates that the matrix \( A \) is singular, meaning it does not have an inverse. ### Conclusion The inverse of the matrix \( A \) does not exist because the determinant is equal to zero. ---

To find the inverse of the matrix \( A = \begin{pmatrix} 6 & -3 \\ -2 & 1 \end{pmatrix} \) using elementary operations, we will follow these steps: ### Step 1: Calculate the Determinant of Matrix A The determinant of a 2x2 matrix \( \begin{pmatrix} a & b \\ c & d \end{pmatrix} \) is calculated using the formula: \[ \text{det}(A) = ad - bc \] For our matrix \( A \): ...
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