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Using the property of determinants and without expanding in questions 1 to 7 prove that ,
`|{:(x,a,x+a),(y,b,y+b),(z,c,z+c):}|=0`

Text Solution

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`L.H.S.=|{:(x,a,x+a),(y,b,y+b),(z,c,z+c):}|=|{:(x,a,0),(y,a,0),(z,c,0):}|`
`(C_(3)toC_(3)-C_(1)-C_(2))`
`=" "(therefore" all elements of "C_(3)" are zero")`
=R.H.S.
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