Find the vector and equation of a plane which is at a distance of 10 units from origin and normal vector from origin to this plane is `2hati-hatj+2hatk`.

Explanation

To find the vector and equation of a plane that is at a distance of 10 units from the origin with a normal vector given by \( \mathbf{n} = 2\hat{i} - \hat{j} + 2\hat{k} \), we can follow these steps:

### Step 1: Identify the normal vector and distance
The normal vector \( \mathbf{n} \) is given as:
\[ \mathbf{n} = 2\hat{i} - \hat{j} + 2\hat{k} \]
The distance \( p \) from the origin to the plane is given as:
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