Find the normal form of the plane `2x+3y-z = 5`. Also find the length of perpendicular from origin and d.c's of the normal to the plane.

Explanation

To find the normal form of the plane given by the equation \(2x + 3y - z = 5\), as well as the length of the perpendicular from the origin and the direction cosines of the normal to the plane, we will proceed step by step.

### Step 1: Write the equation of the plane
The equation of the plane is given as:
\[ 2x + 3y - z = 5 \]

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