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Find the vector equation of the followin...

Find the vector equation of the following plane in product form `vecr = ( hati-hatk)+lambda(hati+2hatj)+mu(hati+3hatj-hatk)`.

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Comparing with `vecr = veca+lambdavecb+muvecc`
`veca=hati-hatk,vecb=hati+2hatj,vecc=hati+3hatj-hatk`
`vecn=vecbxxvecc=|{:(hati,hatj,hatk),(1,2,0),(1,3,-1):}|`
`=hati(-2-0)-hatj(-1-0)+hatk(3-2)`
`=-2hati+hatj+hatk`
Equation of plane
`vecr.vecn=veca.vecn`
`rArr vecr.(-2hati+hatj+hatk) = (hati-hatk).(-2hati+hatj+hatk)`
`= -2-1`
`= - 3`
`rArr vecr.(-2hati+hatj+hatk) = - 3`
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Find the vector equation of the following planes in cartesian form : " "vecr=hati-hatj+lamda(hati+hatj+hatk)+mu(hati-2hatj+3hatk) .

Find the vector equation of the plane in which the lines vecr=hati+hatj+lambda(hati+2hatj-hatk) and vecr=(hati+hatj)+mu(-hati+hatj-2hatk) lie.

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Convert the equation of the plane vecr = (hati-hatj)+lambda(-hati+hatj+2hatk)+mu(hati+2hatj+hatk) into scalar product form.

Find the shortest distance between the following pair of line: vecr=hati+hatj+lamda(2hati-hatj+2hatk), vecr=2hati+hatj-hatk+mu(3hati-5hatj+2hatk)

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