Find the perpendicular distance from the point `(1,-3,4)` to the plane `3x-4y+12z - 1 = 0`.

Explanation

To find the perpendicular distance from the point \( (1, -3, 4) \) to the plane given by the equation \( 3x - 4y + 12z - 1 = 0 \), we can use the formula for the distance \( D \) from a point \( (x_1, y_1, z_1) \) to a plane \( Ax + By + Cz + D = 0 \):

\[ D = \frac{|Ax_1 + By_1 + Cz_1 + D|}{\sqrt{A^2 + B^2 + C^2}} \]

### Step-by-Step Solution:

...