Find the Cartesian equation of the line which passes through the point (-2, 4, -5) and is parallel to the line `(x+3)/3=(4-y)/5=(z+8)/6dot`

Explanation

The direction ratios of the line `(x+3)/(3) = (y-4)/(5) = (z+8)/(6)` are `(3,5,6)`.
Here the line passes through the point (-2,4,-5) and the direction ratios of the parallel line are `(3,5,6)` . So, the equation of line is,
`(x-(-2))/(3) = (y-4)/(5) = (z-(-5))/(6)`
`rArr (x+2)/(3) = (y-4)/(5) = (z+5)/(6)`