Find the vector and Cartesian equation of the plane that passes through the point (1,4,6) and the normal vector to the plane is `hati-2hatj+hatk`.

Explanation

To find the vector and Cartesian equations of the plane that passes through the point \( (1, 4, 6) \) and has a normal vector \( \hat{i} - 2\hat{j} + \hat{k} \), we can follow these steps:

### Step 1: Identify the given information
- Point on the plane: \( A(1, 4, 6) \)
- Normal vector to the plane: \( \mathbf{n} = \hat{i} - 2\hat{j} + \hat{k} \)

### Step 2: Write the vector equation of the plane
The vector equation of a plane can be expressed using the formula:
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