For two events A and B, `P(A)=7/13, P(B)=9/13` and `P(AnnB)=4/13`. Find the value of `P(A//B)`.

Explanation

To find the value of \( P(A|B) \), we will use the formula for conditional probability:

\[ P(A|B) = \frac{P(A \cap B)}{P(B)} \]

### Step-by-Step Solution:

1. **Identify Given Values:**
- \( P(A) = \frac{7}{13} \)
- \( P(B) = \frac{9}{13} \)
- \( P(A \cap B) = \frac{4}{13} \)

2. **Substitute Values into the Conditional Probability Formula:**
- We need to find \( P(A|B) \):
\[ P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{\frac{4}{13}}{\frac{9}{13}} \]

3. **Simplify the Expression:**
- When dividing fractions, we multiply by the reciprocal:
\[ P(A|B) = \frac{4}{13} \times \frac{13}{9} \]
- The \( 13 \) in the numerator and denominator cancels out:
\[ P(A|B) = \frac{4}{9} \]

4. **Final Answer:**
- Therefore, the value of \( P(A|B) \) is:
\[ P(A|B) = \frac{4}{9} \]