Two cards are drawn one by one without replacement. Find the probability that both are hearts.

Answer

N/a

Explanation

Let A and B be the events of drawing first and second card of heart respectively.
`:.` Required probability `=P(Annb)=P(A).P(B//A)`
Now `P(A)=(.^(13)C_(1))/(.^(52)C_(1))=13/52=1/4`
After drawing first card,
Remaining cards `=51`
No. of hearts `=12`
`:.P(B//A)=(.^(12)C_(1))/(.^(51)C_(1))=12/51=4/17`
Now `P(AnnB)=P(A).P(B//A)=1/4xx4/17=1/17`