An unbaised coin is tossed 8 times. Find , by using binomial distribution, the probability of getting at least 6 heads.

Answer

N/a

Explanation

`n=8`
`p=` probability of getting one head in one toss of a coin
`impliesp=1/2`
`:.q=1-p=1-1/2=1/2`
Now probability of getting at least 3 heads.
`P(Xge3)=1-[P(X=0)+P(X=1)+P(X-2)]`
`=1-[.^(8)C_(0)p^(0).q^(8)+.^(8)C_(1)p^(1).q^(7)+.^(8)C_(2)p^(2)q^(6)]`
`=1-[(1/2)^(8)+8 . 1/2 (1/2)^(7)+28.(1/2)^(2)(1/2)^(6)]`
`=1-37/256=219/256`