A die is thrown again and again until three sixes are obtained. Find the probability of obtaining the third six in the sixth throw of the die.

Answer

N/a

Explanation

When a die is thrown then probability of getting the number 6`=1/6`
and probability of not getting the number `6=1-1/6=5/6`
Let `P=1/6` and `q=5/6`
Probability of getting the third 6 in sixth throw
`=P` (getting two 6 in first 5 throws and 6 in the sixth throw)
`=P` (getting two 6 in first 5 throws of a die) `xx1/6`
`=.^(5)C_(2)(1/6)^(2)(5/6)^(3)xx1/6=(5xx4)/(1xx2)xx(5^(3))/(6^(6))`
`=(10xx125)/(6^(6))=625/23328`