If a leap year is selected at random, what is the chance that it will contain 53 Tuesdays?

Answer

N/a

Explanation

Leap year `=366` days
`=52` weeks `+2` days
Leap year will have 53 Tuesday if a day in the remaining two days is Tuesday.
Therefore the following 7 possibilities are there for the remaining 2 days:
(i) Sunday and Monday
(ii) Monday and Tuesday
(iii) Tuesday and Wednesday
(iv) Wednesday and Thursday
(v) Thursday and Friday
(vi) Friday and Saturday
(vii) Saturday and Sunday
The favourable outcomes of 53rd Tuesdar are (ii) and (iii) only in the above 7 possibilities.
`:.` Total number of outcomes `=7`
and number of favourable outcomes `=2`
Therefore required probability `=2/7`