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If A and B are any two events such that `P(A) + P(B) - P(A a n d B) = P(A)`? then(A) `P(B | A) = 1` (B) `P(A | B) = 1`(C) `P(B | A) = 0` (D) `P(A | B) = 0`

A

`P(B//A)=1`

B

`P(A//B)=1`

C

`P(B//A)=0`

D

`P(A//B)=0`

Text Solution

Verified by Experts

The correct Answer is:
A
(b)
Given
`P(A)+P(B)-P(A"and"B)=P(A)`
`impliesP(A)+P(B)-P(AnnB)=P(A)`
`impliesP(B)-P(AnnB)=0impliesP(B)=P(AnnB)`
`implies1=(P(AnnB))/(P(B))`
`implies1=P(A/B) [ :' P(A/B)=(P(AnnB))/(P(B))]`
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