Home
Class 10
MATHS
In the adjoining figure, find the area o...

In the adjoining figure, find the area of the shaded region (Use `pi = 3.14`)

Text Solution

Verified by Experts

Diameter `BD = sqrt(6^(2) + 8^(2)) = sqrt(36 + 64) = sqrt(100) = 10 cm`
Radius `= (10)/(2) = 5 cm`
Area of circle `= pi r^(2) = 3.14 xx 5^(2) = 3.14 xx 25 = 78.50 cm^(2)`
Area of rectangel `ABCD = 8 xx 6 = 48 cm^(2)`
Promotional Banner

Topper's Solved these Questions

  • AREA RELATED TO CIRCLES

    NAGEEN PRAKASHAN ENGLISH|Exercise Problems From NCERT /exemplar|25 Videos
  • AREA RELATED TO CIRCLES

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 12 A|24 Videos
  • ARITHMETIC PROGRESSION

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise Long Answer Question|5 Videos

Similar Questions

Explore conceptually related problems

In the joining figure , find the area of the shaded region.

In figure, find the area of the shaded region [U s epi=3. 14]

In figure, find the area of the shaded region [U s epi=3. 14]

In the given figure, find the area of the shaded region [Use pi=3. 14]

Three semicircles each of diameter 3 cm, a circle of diameter 4.5 cm and a semicircle of radius 4.5 cm are drawn in the adjoining figure. Find the area of the shaded region.

Find the area of the shaded region in Figure.

Find the area of the shaded region in figure.

In the given figure, PQ = 24 cm PR = 7 cm and O is the centre of the circle. Find the area of the shaded region. (Use pi = 3.14 )

Find the area of the shaded region given in figure.

In Figure , ABCD is a prallelogram. A semicircle with centre O and the diameter AB has been drawn and it passes through D. If AB = 12 cm and OD bot AB. Then find the area of the shaded region. (Use pi=3.14 )