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Combination of quadrilateral and circle ...

Combination of quadrilateral and circle : In Figure; ABCD is a trapezium with AB||DC ; AB = 18cm; DC = 32cm and the distance between AB and DC is 14 cm. Circles of Equal radii 7 cm with centres A;B;C and D have been drawn. Then; find the area of the shaded region of the figure.

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To find the area of the shaded region in the trapezium ABCD with circles centered at its vertices, we will follow these steps: ### Step 1: Calculate the Area of the Trapezium The area \( A \) of a trapezium can be calculated using the formula: \[ A = \frac{1}{2} \times (a + b) \times h \] where \( a \) and \( b \) are the lengths of the parallel sides, and \( h \) is the height (distance between the parallel sides). ...
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In figure, ABCD is a trapezium with AB|| DC . AB = 18 cm, DC = 32 cm and distance between AB and DC= 14 cm. If arcs of equal radii 7 cm with centres A, B, C and D have been drawn, then find the area of the shaded region of the figure.

In figure arcs have been drawn with radii 14 cm each and with centres P, Q and R. Find the area of the shaded region .

In the figure, AB is a diameter of the circle with centre O and OA = 7cm. Find the area of the shaded region

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In the given figure, ABCD is a trapezium with angle C = 120^(@), DC = 28 cm and BC = 40 cm. Find : (i) AB

In figure, arcs have been drawn of radius 21 cm each with vertices A , B , C and D of quadrilateral ABCD as centres . Find the area of the shaded region.

Constructed a parallelogram ABCD, when : AB=4.5cm, /_B=120^(@) and the distance between AB and DC = 3.0cm .

In the following figure, ABCD to a trapezium with AB // DC. If AB = 9 cm, DC = 18 cm, CF = 13.5 cm, AP = 6 cm and BE = 15 cm Calculate PE

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