Prove that the area of a circular path of uniform width `h` surrounding a circular region of radius `r` is `pih(2r+h)` .

The area of a circular path of uniform width h surrounding a circular region of radius r is (A) pi (h+2r)r (B) pi h(2r+h)dot (C) pi (h+r) r (D) pi (h+r) h

There is a path of uniform width 7 m round and outside a circular garden of diameter 210 m. Find the area of the path.

The flux of electric field through the circular region of radius r as shown in the figure is

A circular field of radius 105 m has a circular path of uniform width of 5 m along and inside its boundary. Find the area of the path.

A circular field of radius 41 m has a circular path of uniform width 5 m along and inside its boundary . Find the cost of paving the path at Rs. 25 per sq . Metre .

A body of mass m is moving in a circular orbit of radius R about a planet of mass M. At some instant, it splits into two equal masses. The first mass moves in a circular orbit of radius R/2 . And the other mass, in a circular orbit of radius (3R)/(2) . The difference between the final and initial total energies is :

The period of a satellite in a circular orbit of radius R is T. What is the period of another satellite in a circular orbit of radius 4 R ?

Charge q_(2) is at the centre of a circular path with radius r. work done in carrying charge q_(1) once around this equipotential path , would be

Two satellites , A and B , have masses m and 2m respectively . A is in a circular orbit of radius R , and B is in a circular orbit of radius 2R around the earth . The ratio of their energies , K_A/K_B is :

Two satellites, A and B, have masses m and 2m respectively. A is in a circular orbit of radius R, and B is in a circular orbit of radius 2R around the earth. The ratio of their kinetic energies, T_(A)//T_(B) , is :