Home
Class 10
MATHS
The area of a semicircle is 308 cm^(2). ...

The area of a semicircle is `308 cm^(2)`. Find its perimeter

Text Solution

AI Generated Solution

The correct Answer is:
To find the perimeter of a semicircle given its area, we can follow these steps: ### Step 1: Understand the formula for the area of a semicircle. The area \( A \) of a semicircle is given by the formula: \[ A = \frac{1}{2} \pi r^2 \] where \( r \) is the radius of the semicircle. ### Step 2: Set up the equation with the given area. We are given that the area of the semicircle is \( 308 \, \text{cm}^2 \). Therefore, we can set up the equation: \[ \frac{1}{2} \pi r^2 = 308 \] ### Step 3: Substitute the value of \( \pi \). Using \( \pi \approx \frac{22}{7} \), we can substitute this value into the equation: \[ \frac{1}{2} \times \frac{22}{7} \times r^2 = 308 \] ### Step 4: Simplify the equation. Multiplying both sides by 2 to eliminate the fraction gives: \[ \frac{22}{7} r^2 = 616 \] Now, multiply both sides by \( 7 \): \[ 22 r^2 = 616 \times 7 \] Calculating \( 616 \times 7 \): \[ 22 r^2 = 4312 \] ### Step 5: Solve for \( r^2 \). Now divide both sides by \( 22 \): \[ r^2 = \frac{4312}{22} \] Calculating this gives: \[ r^2 = 196 \] ### Step 6: Find the radius \( r \). Taking the square root of both sides: \[ r = \sqrt{196} = 14 \, \text{cm} \] ### Step 7: Calculate the perimeter of the semicircle. The perimeter \( P \) of a semicircle is given by the formula: \[ P = \pi r + 2r \] Substituting the value of \( r \) and \( \pi \): \[ P = \frac{22}{7} \times 14 + 2 \times 14 \] ### Step 8: Simplify the perimeter calculation. Calculating \( \frac{22}{7} \times 14 \): \[ \frac{22 \times 14}{7} = 44 \] Calculating \( 2 \times 14 \): \[ 2 \times 14 = 28 \] Now, adding these two results: \[ P = 44 + 28 = 72 \, \text{cm} \] ### Final Answer: The perimeter of the semicircle is \( 72 \, \text{cm} \). ---
Promotional Banner

Topper's Solved these Questions

  • AREA RELATED TO CIRCLES

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise Short Answer Question|12 Videos
  • AREA RELATED TO CIRCLES

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise Long Answer Question|5 Videos
  • AREA RELATED TO CIRCLES

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 12 B|32 Videos
  • ARITHMETIC PROGRESSION

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise Long Answer Question|5 Videos

Similar Questions

Explore conceptually related problems

The area of a garden in the shape of a square is 5184 m^(2) . Find its perimeter .

The area of a square is 169 cm^(2) . Find its : (i) one side (ii) perimeter

The perimeter of a semicircular plate is 108 cm, find its area.

The base of an isosceles triangle is 12 cm and its perimeter is 32 cm . Find its area .

The base of an isosceles triangle is 12 cm and its perimeter is 32 cm. Find the area of the triangle.

The base of an isosceles triangle is 24 cm and its area is 60 cm^(2) Find its perimeter.

It the difference between the sides of right angles triangle is 3 cm and its area is 54 cm^(2) . Find its perimeter.

The perimeter of a circular plate is 132 cm. Find its area

The side of a square is 70cm. Find its area and perimeter.

The area of a rhombus is 72 c m^2 . If its perimeter is 32 cm, find its altitude.