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The inner and outer radius of a circular...

The inner and outer radius of a circular track are 56 m and 63m respectively. Find the area of the track

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To find the area of the circular track, we will follow these steps: ### Step 1: Identify the inner and outer radius - The inner radius (r) is given as 56 m. - The outer radius (R) is given as 63 m. ### Step 2: Calculate the area of the outer circle The formula for the area of a circle is given by: \[ \text{Area} = \pi R^2 \] Substituting the outer radius: \[ \text{Area of outer circle} = \pi (63)^2 \] Calculating \(63^2\): \[ 63^2 = 3969 \] Thus, \[ \text{Area of outer circle} = \pi \times 3969 \] ### Step 3: Calculate the area of the inner circle Using the same formula for the inner circle: \[ \text{Area of inner circle} = \pi (56)^2 \] Calculating \(56^2\): \[ 56^2 = 3136 \] Thus, \[ \text{Area of inner circle} = \pi \times 3136 \] ### Step 4: Calculate the area of the track The area of the track is the difference between the area of the outer circle and the area of the inner circle: \[ \text{Area of track} = \text{Area of outer circle} - \text{Area of inner circle} \] Substituting the areas we calculated: \[ \text{Area of track} = \pi \times 3969 - \pi \times 3136 \] Factoring out \(\pi\): \[ \text{Area of track} = \pi (3969 - 3136) \] Calculating the difference: \[ 3969 - 3136 = 833 \] Thus, \[ \text{Area of track} = \pi \times 833 \] ### Step 5: Substitute the value of \(\pi\) Using \(\pi \approx \frac{22}{7}\): \[ \text{Area of track} = \frac{22}{7} \times 833 \] ### Step 6: Calculate the final area Calculating: \[ \text{Area of track} = \frac{22 \times 833}{7} \] Calculating \(22 \times 833\): \[ 22 \times 833 = 18326 \] Now, divide by 7: \[ \text{Area of track} = \frac{18326}{7} \approx 2618 \] ### Final Answer The area of the track is approximately: \[ \text{Area of track} \approx 2618 \, \text{m}^2 \] ---
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