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A circle field has perimeter 660m. Plot ...

A circle field has perimeter 660m. Plot in the shape of a square having its vertices on the circumference is marked in the field. Calculate the area of the square field

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To solve the problem step by step, we will follow these instructions: ### Step 1: Find the radius of the circle The perimeter (circumference) of the circle is given as 660 m. The formula for the circumference of a circle is: \[ C = 2\pi r \] Setting this equal to the given perimeter: \[ 2\pi r = 660 \] To find the radius \( r \), we rearrange the equation: \[ r = \frac{660}{2\pi} \] Using \( \pi \approx \frac{22}{7} \): \[ r = \frac{660}{2 \times \frac{22}{7}} \] Calculating this gives: \[ r = \frac{660 \times 7}{2 \times 22} \] \[ r = \frac{4620}{44} \] \[ r = 105 \text{ m} \] ### Step 2: Find the diameter of the circle The diameter \( d \) of the circle is twice the radius: \[ d = 2r = 2 \times 105 = 210 \text{ m} \] ### Step 3: Relate the diameter to the square The square inscribed in the circle has its diagonal equal to the diameter of the circle. Therefore, the diagonal \( d \) of the square is: \[ d = 210 \text{ m} \] ### Step 4: Find the side length of the square For a square, the relationship between the side length \( s \) and the diagonal \( d \) is given by: \[ d = s\sqrt{2} \] Rearranging to find \( s \): \[ s = \frac{d}{\sqrt{2}} = \frac{210}{\sqrt{2}} \] To simplify: \[ s = 210 \times \frac{\sqrt{2}}{2} = 105\sqrt{2} \text{ m} \] ### Step 5: Calculate the area of the square The area \( A \) of the square is given by: \[ A = s^2 = (105\sqrt{2})^2 \] Calculating this: \[ A = 105^2 \times 2 = 11025 \times 2 = 22050 \text{ m}^2 \] ### Final Answer The area of the square field is: \[ \text{Area} = 22050 \text{ m}^2 \] ---
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