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A game of chance consists of spinning an...

A game of chance consists of spinning an arrow which is equally likely to come to rest pointing to all of the numbers 1, 2, 3, ...,12. What is the probability that it will point to (i) 10 (ii) an odd number (iii) a number which is multiple of 3?

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To solve the problem, we need to calculate the probabilities for three different scenarios based on the game of chance involving spinning an arrow on a board numbered from 1 to 12. ### Step-by-step Solution: 1. **Total Outcomes**: The total number of outcomes when spinning the arrow is the total number of numbers on the board, which is from 1 to 12. Therefore, the total outcomes = 12. 2. **(i) Probability of pointing to 10**: ...
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