Find the probability of having 53 Tuesdays in a :
(i) non-leap year (ii) leap year.

Explanation

(i) A non-leap year cofltains 365 days. So, on dividing it by 7, we get 52 weeks and 1 more day.
So, since 52 weeks are there, it means 52 Tuesdays will also be there necessarily with probability I and 1 more day may be either Sun. or Mon. or Tue. or Wed. or Thur. or Fri. or Sat.
So, to get 53 Tuesdays, we have to select one more Tuesday from these 7 possibilities with Probability `(1)/(7).`
Therefore, probability of having 53 Tuesdays in a non-leap year `=1xx(1)/(7)=(1)/(7)`
(ii) In a leap year, there are. 366 days and 364 days make 52 weeks and therefore 52 Tuesdays. So, probability of getting 52" Tuesdays till now is 1 (sure event). The remaining two days can be
`{:("Sunday","Monday"),("Monday","Tuesday"),("Tuesday","Wednesday"),("Wednesday","Thursday"),("Thursday","Friday"),("Friday","Saturday"),("Saturday","Sunda"):}`
Hence, favourable outcomes =2 and total outcomes = 7.
Therefore, probability of having 53 Tuesdays in a leap year is `1xx(2)/(7)=(2)/(7).`