A child has die whose six faces show the letters as given below:

The die is thrown once. What is the probability of getting (i) A, (ii) D?

Explanation

Total number of outcomes of a six face die, n(s) = 6
(i) Let `E_(1)`= Event of getting a letter A.
`therefore" "n(E_(1)) =2`
Probability of getting a letter A `= (n(E_(1)))/(n(S)) = (18)/(90)= (1)/(5)`
(ii) Let `E_(2)` = Event of getting a letter D .
`therefore" "n(E_(2)) = 1`
Probability of getting a letter `D =(n(E_(2)))/(n(S)) = (1)/(6)`