What is the smallest number that, when divided by 35,56 and 91 leaves remainder of 7.

Explanation

To find the smallest number \( N \) that, when divided by 35, 56, and 91, leaves a remainder of 7, we can follow these steps:

### Step 1: Set Up the Equation
Let \( N \) be the number we are looking for. According to the problem, we can express \( N \) in terms of the divisors and the remainder:
- When \( N \) is divided by 35, it can be expressed as:
\[ N = 35k + 7 \quad (1) \]
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